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Finding Fmax

  1. Oct 18, 2009 #1
    1. The problem statement, all variables and given/known data
    Two boxes sit on a table, connectedn by a massless string. The first is 2.0 kg and the second is 3.0 kg. The coefficient of kinetic friction betweent the boxes and the table is 0.80. The max tensile strength is 1000 N. What is the max force that can be exerted on the 3.0 kg box to make the system accelerate?

    2. Relevant equations

    3. The attempt at a solution
    Normal Force on 2.0 kg box:
    Fn=mg=2.0(9.8)=19.6 N
    Normal Force on 3.0 kg box:
    Fn=mg=3.0(9.8)=29.4 N
    Total Amount of Friction:
    Fk=uk(Fn2.0+Fn3.0)=0.8(19.6+29.4)=39.2 N

    Now I am stuck..
  2. jcsd
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