What is the heat of a system when it expands by 0.67 m^3?

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To find the heat of a system expanding by 0.67 m^3 at a constant pressure of 105 kPa, the relevant equations are deltaU = Q - W and W = P * deltaV. The internal energy decreases by 1710J, which is used to calculate the work done during expansion. The user initially struggled with the calculations but identified an error in their process while explaining it. Correct application of the equations will yield the heat of the system.
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Homework Statement


A system expands by 0.67 m^3 at a constant pressure of 105 kPa. Find the heat of the system if its internal energy decreases by 1710J.


Homework Equations


Since P=constant:
deltaU=Q-W
W=PdeltaV


The Attempt at a Solution


I tried plugging in the numbers to the equation for W and then plugging that value into the first equation to solve for U, but I didn't get the correct answer and I'm not sure where I went wrong.
 
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Nobody will know where you went wrong if you don't say what you plugged into where and what came out of that process.
 
sorry, but while I was typing my process just now I realized what went wrong. Thank you!
 

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