(adsbygoogle = window.adsbygoogle || []).push({}); A 30mH solenoid inductor is wound on a form 0.4 m in length and 0.1 m in diameter. A coil is tightly wound around the solenoid at its center. the coil resistance is 5.0 ohms. The mutual inductance of the coil and solenoid is 60μH. At a given instant, the current in the solenoid is 0.3A and is decreasing at a rate of 2.5A/s.

a) Find the number of turns in the winding of the solenoid

b) Find the induced emf at the given instant.

c) At the given instant, the flux linkage N(phi) for the solenoid is...

Hey guys, really need a nice simple answer here, thank you...I'm new to the forum by the way :D

At first I used the formula mu(n1)(n2)A/L equals the mutual inductance but now Im stumped since you have 2 unknowns and I don't know how to find one of them

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# Finding induced emf, number of turns, and flux linkage of coil wound around solenoid

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