Finding Mass of part of a block that explodes.

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A block explodes into two pieces, L and R, with known masses and distances they slide before stopping due to friction. Piece L has a mass of 2.5 kg and stops after sliding 0.28 m with a kinetic friction coefficient of 0.44, while piece R slides 0.30 m with a coefficient of 0.43. The conservation of momentum principle applies, as the initial momentum of the stationary block is zero, meaning the momentum of the two pieces must equal each other post-explosion. To find the mass of the original block, one can use equations relating friction, deceleration, and distance traveled. Understanding these relationships and applying the correct equations is crucial for solving the problem effectively.
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1.In Fig. 9-59, a stationary block explodes into two pieces L and R that slide across a frictionless floor and then into regions with friction, where they stop. Piece L, with a mass of 2.5 kg, encounters a coefficient of kinetic friction μL = 0.44 and slides to a stop in distance dL = 0.28 m. Piece R encounters a coefficient of kinetic friction μR = 0.43 and slides to a stop in distance dR = 0.30 m. What was the mass of the block?


http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c09/fig09_57.gif




2. v2=v02+2*a*x-x0
momentum=m*v




3. I really have no idea where to start on this one, can someone give me a place to go from. somehow i tried to us this
sqrt(mew*g*d*2) to get the velocity for the block on the left, then plugged that into the sum of momentum equation, however when i turned it in i got it wrong


 
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do you know the equation for the force of friction relating mass & u?

you know about the conservation of momentum I presume, so if it's stationary at first it has a momentum of 0, so after the collision what must the momentum of the others be equal to?

when you've got this grounded I would consider the equations of motions, with the initial velocity of the block being v, you should have a constant deceleration.
 
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