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BrownPrincezz
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I graphed Magnetic Field (T) vs Current (A) and my slope was equal to 0.0012 which is off by 10^-3. Can someone suggest why this could be happening?
Finding permability of free space from Magnetic Field vs. Current graph
- Thread starter BrownPrincezz
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AI Thread Summary
The discussion centers on a graph plotting Magnetic Field (T) against Current (A), where the calculated slope is 0.0012, deviating by 10^-3. The user converted Magnetic Field data from Gauss to Tesla and provided specific current values in Amperes. Participants are asked to suggest reasons for the slope discrepancy and inquire about the data used for plotting the graph. The conversation emphasizes the importance of accurate data conversion and potential sources of error in the experimental setup. Understanding these factors is crucial for determining the permeability of free space accurately.
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system
$$M(t) = M_{C} + m(t)$$
$$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$
$$P_i = Mv + u \, dm$$
$$P_f = (M + dm)(v + dv)$$
$$\Delta P = M \, dv + (v - u) \, dm$$
$$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$
$$F = u \frac{dm}{dt} = \rho A u^2$$
from conservation of momentum , the cannon recoils with the same force which it applies.
$$\quad \frac{dm}{dt}...
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