Finding resistance and temp co-efficient

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The motor winding's resistance increased from 80 ohms at 20°C to 100 ohms after four hours of operation. Using the temperature coefficient of resistance (α = 1/234.5°C), the temperature rise was calculated to be 63.63°C, resulting in a final temperature of 83.63°C. The calculation does not consider the initial temperature in Kelvin, which would be 293.5K, but the final result remains valid. The discussion confirms that the solution is correct, and the answer of 83.63°C is acceptable. Overall, the analysis effectively demonstrates the relationship between resistance and temperature change in the motor winding.
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Homework Statement


A motor winding has a risitance of 80 ohm at room temperature of 20c before
switching on to a 230v. after 4 hour run wionfing resistance is 100 ohm
find the temperature rise if the matrial resistance temperature co-efficient is 1/234.5/c.

R at 20 = 80 ohm
R at t = 100 ohm
alpha =1/234.5

Homework Equations


R at 20/R at t = R at 0c (1 - at)/ R at 0c (1-at)


The Attempt at a Solution



80/100 = 1+0.004264X20/1+0.004264t

t = 83.630 c

Rise is t-20 = 83.630-20
t rise is 63.63 c
 
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The rise does not take into acount the initial temperature as if it were in Kelvin it would have been 293.5. The actual result should be 83.63.
 
Lok said:
The rise does not take into acount the initial temperature as if it were in Kelvin it would have been 293.5. The actual result should be 83.63.


but solution is right? and answer 83.63 is ok with this statement
 

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