1. The problem statement, all variables and given/known data 2. Relevant equations Law of Superposition I=V/R 3. The attempt at a solution I am reducing the circuit. i) By law of Superposition, short circuit V2 100 ohms on the leftmost branch and 50 ohms on the rightmost branch, both are in parallel so 100*80/(100+80)=44.4 ohms seen by V1(t) ii) I=V/R I=2/44.4 I=0.045 A iii) short circuit V1 reduce the circuit, 60+40+80=180 ohms as all the resistors are in series. iv) I=V/R I=10/180 I=1/18 A v)Using law of super position By shorting V2 I obtain I=0.02A By shorting V1 I obtain I= 1/18A I = 0.02+1/18 = 0.076A Please correct me where I am going wrong. Your help is appreciated. Thanks!