Finding specific heat capacity of a non-monatomic (ideal gas)

AI Thread Summary
The discussion revolves around calculating the change in internal energy and the molar specific heat capacity (Cp) for a non-monatomic ideal gas undergoing isobaric expansion. The first law of thermodynamics is applied, where the change in internal energy (ΔU) can be determined using the equation ΔU = Q - PΔV. The relationship between enthalpy (ΔH), internal energy, and heat added is also highlighted, indicating that ΔH equals the heat added (Q) at constant pressure. To find Cp, the user is guided to use the ratio ΔH/ΔU and the relationship between Cp and Cv, which includes the gas constant R. The conversation emphasizes the importance of understanding the properties of non-monatomic gases in thermodynamic calculations.
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Homework Statement



Suppose that 31.4 J of heat is added to an ideal gas. The gas expands at a constant
pressure of 1.40x104 Pa while changing its volume from 3.00x104 to 8.00x104 m3.
The gas is not monatomic, so the relation CP = 5/2R does not apply. (a) Determine the
change in the internal energy of the gas. (b) Calculate its molar specic heat capacity
CP .

Homework Equations


The Attempt at a Solution



I have completed part a) using the knowledge that it is an isobaric process, but I'm a bit unsure of my answer for b)

My textbook says that for a diatomic ideal gas, Cp is given by 7/2 R, but the question only says the gas is not monatomic.

Is there a piece of info I'm missing?

Thanks!
 
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Because U is a state variable, you can define a path between the initial and final states of the gas where V is a constant. This will allow you to find cv, from which you can extract cp.
 
BOAS said:

Homework Statement



Suppose that 31.4 J of heat is added to an ideal gas. The gas expands at a constant
pressure of 1.40x104 Pa while changing its volume from 3.00x104 to 8.00x104 m3.
The gas is not monatomic, so the relation CP = 5/2R does not apply. (a) Determine the
change in the internal energy of the gas. (b) Calculate its molar specic heat capacity
CP .

Homework Equations





The Attempt at a Solution



I have completed part a) using the knowledge that it is an isobaric process, but I'm a bit unsure of my answer for b)

My textbook says that for a diatomic ideal gas, Cp is given by 7/2 R, but the question only says the gas is not monatomic.

Is there a piece of info I'm missing?

Thanks!
Just apply the constant pressure version of the first law: ΔU=Q-PΔV. Also, since ΔH=ΔU+Δ(PV), which for this constant pressure process becomes ΔH=ΔU+PΔV. So, for this process ΔH=Q. For an ideal gas, ΔH=CpΔT and ΔU=CvΔT. So,
ΔH/ΔU=Cp/Cv=(Q-PΔV)/Q. You also know that Cp-Cv for an ideal gas is equal to R. This should give you enough information to determine Cp.
 
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