- #1

CentreShifter

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## Homework Statement

The electric potential at points in an xy plane is given by V = (2.7 V/m

^{2})x

^{2}-(4.4 V/m

^{2})y

^{2}. What are (a) the magnitude of the electric field at the point (3.4 m, 1.6 m) and (b) the angle that the field there makes with the positive x direction.

## Homework Equations

I have already taken the partial derivatives of V with respect to x and y to get the components to the field and then the magnitude. E

_{x}=18.36 V/m and E

_{y}=-14.08 V/m

## The Attempt at a Solution

The magnitude of the field at the given point is 23.137 V/m. I absolutely cannot for the life of me figure out how to calculate that angle, and I know it's in front of my face. I've tried arctan, but it just doesn't work.