Finding the coefficient of kinetic friction

Click For Summary

Homework Help Overview

The problem involves a 50 kg block sliding down a 32° ramp with a specified acceleration, and the objective is to determine the coefficient of kinetic friction between the block and the ramp.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between the forces acting on the block and the coefficient of kinetic friction. Some participants suggest using a free body diagram and Newton's second law to analyze the forces involved.

Discussion Status

The discussion includes attempts to clarify the steps needed to approach the problem, with some guidance offered regarding the identification of forces. However, there is no explicit consensus on the method, and the original poster expresses some confusion about the relationship between net force and frictional force.

Contextual Notes

The original poster indicates difficulty in applying the suggested methods and seeks a simpler explanation. There may be assumptions about the understanding of forces and their components that are being questioned.

physics_fool
Messages
3
Reaction score
0

Homework Statement



A 50 kg block slides down a 32° ramp with an acceleration of 3.2 m/s2.
What is the coefficient of kinetic friction between the block and the ramp?

Homework Equations


[tex]\mu[/tex]kinetic=[tex]\frac{f_{kinetic}}{F_{normal}}[/tex]


The Attempt at a Solution



I have gone through many attempts, but all of them just don't seem right...could someone please explain it plain and simple?
 
Physics news on Phys.org
Hi physics_fool, welcome to PF. The usual algorithm for solving such problems is:

1) Draw a free body diagram, identifying the forces. There should be weight, friction, and normal force.
2) Use Newton's second law, F=ma, to find the force of friction
3) Use Force of friction / Normal Force = coefficient of friction

So what are the components of the forces in each direction?
 
That's the question as it was given...

but for your second question, isn't that to find the net force...not the force of friction?
 
Ok...nvm. I got it...thanks anyways:smile:
 

Similar threads

Replies
18
Views
3K
  • · Replies 16 ·
Replies
16
Views
6K
Replies
2
Views
901
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 28 ·
Replies
28
Views
6K
  • · Replies 32 ·
2
Replies
32
Views
4K
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
48
Views
8K