Finding the coefficient of static friction

AI Thread Summary
To find the coefficient of static friction for a car on a banked curve, the problem involves analyzing forces acting on the car at different speeds. The relevant equations include centripetal force and the components of friction and normal force. The user attempted to set up equations but struggled with breaking down the forces correctly. After converting speeds and applying the equations, they calculated a static friction coefficient of 0.81, but expressed uncertainty about the accuracy of this result. Clarification on the components of the forces was requested to ensure the calculations were correct.
dapperjon002
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Homework Statement


If a curve with a radius of 85m is properly banked for a car traveling 65 km/h what must the coefficiant of static friction be for a car not to skid when traveling at 95km/h


Homework Equations


For this question i tried using a few equations such as centripical force, force friction where Ffric = UsFn as well as (mv^2)/R = Ffric i also though the equation Tan(theta)=V^2D/Rg was pertanent.


The Attempt at a Solution


I set up a proportion of mv^2/R = Us(ma) and the masses canceled out so i was left with v^2/ra but i didnt really know where to go from here.
 
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Welcome to Physics Forum, although I am quite new too.
The car is moving on a banked curve. Did you take in account the part of the normal force that points towards the centre N_{x}? Also, you should also break the friction force into components f_{x} and f_{y}.
 
Ok i set up my two force components and i have Fycos(theta)=mg and Fxsin(theta)=mv^2/r when dividing both components together you are left with tan(theta)=v^2/rg and when i plug in the numbers given after converting 95 km/h to m/s you get a static friction of .81 am i doing somthing wrong because it doesn't seem right
 
dapperjon002 said:
Fycos(theta)=mg and Fxsin(theta)=mv^2/r

What did you mean by Fy and Fx?
 
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