Finding the Distance for a Projectile to Land on a Moving Cart

  • Thread starter Thread starter judas_priest
  • Start date Start date
  • Tags Tags
    Cart Projectile
AI Thread Summary
To determine the distance d for a projectile to land on a moving cart, the time taken for the ball to fall from height h must be equated with the time it takes for the cart to travel distance d. The equation x/v1 = (d-x)/v2 is used, where x represents the horizontal distance traveled by the ball. The height h is crucial as it influences the time the ball is in the air, thus affecting the horizontal displacement. A second equation is necessary to solve for d definitively, incorporating the effects of height on the projectile's motion. Understanding these relationships is essential for finding the correct distance d.
judas_priest
Messages
174
Reaction score
0

Homework Statement


A ball is kicked horizontally with speed v1 from the top of a building of height h. A small cart is moving towards the building with a constant speed v2. Right at the instant when the ball is kicked, the cart is at a distance d from the building. What is the distance d so that the ball lands right on top of the cart? You can neglect the dimensions of the cart with respect to the height of the building h. Express your answer in terms of some or all of the variables h, v1, v2 and g


Homework Equations





The Attempt at a Solution



I tried to equate the time taken (since they meet at the same time). I made sure to include 'd' in my equation, because that's the variable needed to be found

Here's my equation.

x/v1 = d-x/v2.

Where x is the distance traveled by the ball in x direction and d-x is the distance traveled by the cart.

The questions needs an 'h' in the answer. I can't get the term in my answer
 

Attachments

  • Untitled.png
    Untitled.png
    1.8 KB · Views: 459
Physics news on Phys.org
Hmm, the way I see this problem is you first need to find the total horizontal displacement of the ball ( I posted how to do so in your other thread ).

With this in mind, you know exactly how far away the cart will need to be from the building for the ball to land inside of it.
 
I too did it that way. But the answer needs a 'h'. Like the question says.
 
judas_priest said:
I too did it that way. But the answer needs a 'h'. Like the question says.

Express your answer in terms of some or all of the variables h, v1, v2 and g

I don't see how the height of the building is relevant in this case. The height of the building would be used to calculate the total time the ball was in the air.
 
judas_priest said:
x/v1 = d-x/v2.

This is one equation and two unknowns. You need another equation for a definite solution. Think how the height affects the motion.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top