Finding the Effective resistance of a tree of resistors

AI Thread Summary
The discussion focuses on calculating the effective resistance of a tree of resistors that bifurcates three times and the effective resistance of an infinite tree of resistors. Participants suggest using Ohm's Law and simplifying the tree by substituting identical sub-trees with a single resistor of value T ohms. For the finite tree, the calculated effective resistance is proposed to be 15R/8 ohms, while for the infinite tree, the resistance is debated to be R ohms due to the infinite nature of the branches. The conversation emphasizes exploring patterns by analyzing trees with varying branches to better understand the resistance calculations.
Ajonsight
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1. A) Find the Effective resistance of a tree of resistors that bifurcates 3 times.
B) Find the effective resistance of a tree of infinite resistors. (if the tree below went on to infinity)

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Homework Equations


Ohm's Law

The Attempt at a Solution


I have no idea how to start this. There was no other info given either.
 
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Surely you can draw the 3-bifurcation one to completion and solve it? At least give it a try.
 
phinds said:
Surely you can draw the 3-bifurcation one to completion and solve it? At least give it a try.

is it just resistors in series ?
 
Let's denote the resistance of that whole tree as T ohms. We don't know what it will be, yet, but at least we have given it a symbol.

Wherever you look, you find sub-trees that are all identical to that parent. So in place of each of those sub-trees going off to infinity you can substitute a single resistor of value T ohms. This simplifies the figure considerably! !
 
NascentOxygen said:
Let's denote the resistance of that whole tree as T ohms. We don't know what it will be, yet, but at least we have given it a symbol.

Wherever you look, you find sub-trees that are all identical to that parent. So in place of each of those sub-trees going off to infinity you can substitute a single resistor of value T ohms. This simplifies the figure considerably! !

So there's 7 T ohms + R ohms
im just having a hard time seeing if they are in series or parallel
 
Ajonsight said:
So there's 7 T ohms + R ohms
im just having a hard time seeing if they are in series or parallel
I think you mean 8? These will all be going to ground at their farther end.

See whether you can do it using fewer than 8.
 
NascentOxygen said:
I think you mean 8? These will all be going to ground at their farther end.

See whether you can do it using fewer than 8.

is the answer 15R/8 ohms?
 
and for part b would it just be 1 since there's a infinite number of resistors and bifurcations?
 
Ajonsight said:
is the answer 15R/8 ohms?
For (a), yes.
 
  • #10
Ajonsight said:
and for part b would it just be 1 since there's a infinite number of resistors and bifurcations?
You're guessing. ✗[/size][/color]

The resistance is going to have to be at least R.
 
  • #11
Ajonsight said:
is the answer 15R/8 ohms?

Good job !
 
  • #12
NascentOxygen said:
You're guessing. ✗

The resistance is going to have to be at least R.

so the answer to part b is R ohms because it would be infinity over infinity?
 
  • #13
Ajonsight said:
so the answer to part b is R ohms because it would be infinity over infinity?

If you want to really get a sense of what's going on, do it for 1 branch, 2 branches, 3 branches (already done), and maybe 4 branches and see if there is a pattern that you could extrapolate to a limit.
 
  • #14
phinds said:
If you want to really get a sense of what's going on, do it for 1 branch, 2 branches, 3 branches (already done), and maybe 4 branches and see if there is a pattern that you could extrapolate to a limit.

oh ok. so its 2R ohms since is approaching 2R ohms. The next branch added would be 31R/16
 
  • #15
Ajonsight said:
oh ok. so its 2R ohms since is approaching 2R ohms. The next branch added would be 31R/16

Again, good job !
 
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