- #1
Bryster77
- 4
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Find the electric field at a point midway between the two charges of +30.0 x 10^-9 C and +60.0 x 10^-9 C separated by a distance of 30.0cm
My work:
E= Kq / r^2
E= (9 x 10^9 NxM^2/C^2)(30.0 x 10^-9 C)/ (0.30m)^2
i get 3000 N/C
E= (9x10^9 NxM^2/C^2)(60 x 10^-9 C)/(0.30m)^2
i get 6000 N/C
i added the two together and got 9000N/C, but its telling me the answer is "12.0 x 10^3N/C toward 30 nC"
i am confused on what i am doing wrong. please help
My work:
E= Kq / r^2
E= (9 x 10^9 NxM^2/C^2)(30.0 x 10^-9 C)/ (0.30m)^2
i get 3000 N/C
E= (9x10^9 NxM^2/C^2)(60 x 10^-9 C)/(0.30m)^2
i get 6000 N/C
i added the two together and got 9000N/C, but its telling me the answer is "12.0 x 10^3N/C toward 30 nC"
i am confused on what i am doing wrong. please help