Finding the height above a window after an object passes it

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To determine the height above a window after a roof tile falls, the observer notes that the tile takes 0.20 seconds to pass a 1.6-meter window. Newton's equations of motion are essential for solving this problem, particularly the equations v² - u² = 2as and v = u + at. It's important to calculate the velocity at the top of the window using these equations rather than simply dividing the window height by time. Once the velocity is known, the distance from the roof to the top of the window can be calculated. Proper application of these equations will yield the required height above the window.
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Homework Statement


A roof tile falls from rest from the top of a building. An observer inside the building notices that it takes .20s for the tile to pass her window, whose height is 1.6m. How far above the top of the window is the roof?


Homework Equations


just having trouble determining how to solve.


The Attempt at a Solution


 
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Are you familiar with Newton's equations of motion?
 
try v2-u2=2as
v=u+at
s=ut+1/2at2

where u=v0

2 will be used find out which
 
Last edited:
Remember you can't just use 1.6/0.2 to calculate the velocity. One of the equations hav0c provided can be used to calculate the velocity at the top of the window. Another to work out the distance from roof to top of window.
 

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