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## Homework Statement

Find the integral (I think I'm finding the integral) of:

[itex]\frac{dQ}{dt}[/itex] =kQ

## Homework Equations

## The Attempt at a Solution

I just got feedback from my teacher, and he told me I make a mistake somewhere in this question. But I don't know where I've gone wrong?

[itex]\frac{dQ}{dt}[/itex]=kQ

[itex]\frac{dQ}{Q}[/itex]=kdt

∫[itex]\frac{dQ}{Q}[/itex]=∫kdt

lnQ=kt+c

Q=e

^{kt}+e

^{c}

Where e

^{c}is a constant, so let e

^{c}=A

Q=Ae

^{kt}

∴ Q=Ae

^{kt}

Can anyone see where I've gone wrong?

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