Finding the Maximum Electric Field of a Charged Ring

AI Thread Summary
The discussion centers on finding the maximum electric field generated by a charged ring with a radius of 20.6 cm and a total charge of 12 nC. The electric field is expressed as a function of distance from the center of the ring, and participants clarify that the field is zero at the center and increases before decreasing again as distance increases. To find the maximum electric field, the derivative of the electric field function must be set to zero. There is some confusion regarding the variables in the equation, specifically whether 'R' refers to the radius of the ring or the distance from the charge to the point of interest. The key takeaway is that understanding the relationship between these variables is crucial for correctly determining the maximum electric field.
05holtel
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Homework Statement




Consider a charged ring of radius 20.6 cm and total charge 12 nC.

We are interested in the electric field a perpendicular distance z away from the center of the ring.

At what distance from the center of the ring does the electric field become maximum?

Hint: The field for a ring of charge is:

Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2))

Homework Equations




The Attempt at a Solution



When x = 0, the fields due to segments of the ring cancel out. As x -> infinity, the field falls with 1/x^2 behavior, so there has to be a maximum E for some x.

When adding up the fields due to each arc segment, you only have to add the x-components (along the axis) because the others will cancel out.

Here is what I get for E as a function of x:

E (x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)]
The second term in brackets is the cosine of the angle that defines the component in the x direction.

That function must be differentiated to find where the field is a maximum.


1) is this right so far
2) if so how do I differentiate this
 
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05holtel said:

Homework Statement




Consider a charged ring of radius 20.6 cm and total charge 12 nC.

We are interested in the electric field a perpendicular distance z away from the center of the ring.

At what distance from the center of the ring does the electric field become maximum?

Hint: The field for a ring of charge is:

Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2))

Homework Equations




The Attempt at a Solution



When x = 0, the fields due to segments of the ring cancel out. As x -> infinity, the field falls with 1/x^2 behavior, so there has to be a maximum E for some x.

When adding up the fields due to each arc segment, you only have to add the x-components (along the axis) because the others will cancel out.

Here is what I get for E as a function of x:

E (x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)]
The second term in brackets is the cosine of the angle that defines the component in the x direction.

That function must be differentiated to find where the field is a maximum.


1) is this right so far
2) if so how do I differentiate this

Well if the field starts off at zero at x= 0 then increases, and then dies off again, then I think we would look at where dE/dx = 0 as this is where the slope of an E v. x graph would be maximum.

In the equation given, they give you the e-field function of this ring, with Z being your X? Or is Z supposed to be the radius of the ring, or is R the radius of the ring and not the distance from a specific segment of the ring of charge to the point of interest?
 
In others words, r is usually the distance from some charge to some place you are looking for the E field. In the equation you were given, is r the radius of the charged ring, or the distance from the charge to the place of interest..?
 
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