Finding the min value of an expression

  • Thread starter Thread starter superconduct
  • Start date Start date
  • Tags Tags
    Expression Value

Which area in math you prefer to investigate further?

  • Algebraic Number Theory, Algebraic Geometry, and Representation Theory

    Votes: 0 0.0%
  • Topology and Geometry

    Votes: 2 100.0%
  • Applied Analysis, Control Theory and Game Theory

    Votes: 0 0.0%
  • Combinatorics

    Votes: 0 0.0%
  • Scientific Computing and Numerical Analysis

    Votes: 0 0.0%
  • Probability

    Votes: 0 0.0%

  • Total voters
    2
superconduct
Messages
31
Reaction score
1

Homework Statement


a,b,c,d are real numbers
ab+bc+cd+da=16
Find the minimum value possible for a²+b²+c²+d²


Homework Equations


ab+bc+cd+da = (a+c)(b+d)
x^2 \ge 0 for some real x

The Attempt at a Solution


1st approach:2(a^2 +b^2 +c^2 +d^2) + 2(ab+bc+cd+da) = (a+b)^2 +(b+c)^2 +(c+d)^2 +(d+a)^2 \ge 0
which gives a^2 +b^2 +c^2 +d^2 \ge -16 that cannot give the min. value.

2nd approach: (a+c)(b+d) =16
By differential calculus, rectangle of fixed area has min. diagonal when it is square,
a+c=b+d=4
a=b=c=d=2
a^2 +b^2 +c^2 +d^2 \ge 2^2+2^2+2^2+2^2 =16

How would you solve this? If you think there is any unclear reasonings in my post or others' replies please do not mind elaborating/criticizing/replacing them for me and others.
 
Physics news on Phys.org
Your first approach is good, but try subtracting instead of adding. Then you can demonstrate (as you have) that the lowest answer is achievable.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top