Finding the Net Force on a Box on an Inclined Plane

AI Thread Summary
To find the net force on a box on an inclined plane, consider the forces acting parallel to the incline: the gravitational component mg(sin q) and the kinetic friction force uk(mg cos q). The net force can be calculated using the equation F_net = mg(sin q) - uk(mg cos q). The discussion confirms that this approach is correct and clarifies that only these two forces are relevant. Understanding this simplifies the problem significantly.
chiurox
Messages
35
Reaction score
0

Homework Statement



A box of mass, m, is on a plane inclined at an angle, q, relative to the horizontal. The coefficient of kinetic friction between the box and the incline is uk, and the body is accelerating down the incline. What is the net force on the body?

The Attempt at a Solution



Well, if the box is accelerating down the incline, the mg(sinTheta) vector of the box must be greater than the Ffriction. But I don't know how to go from there.
I'm guessing it's mg (sin q - uk cos q) but I'm not sure. Could anything clarify for me?
 
Physics news on Phys.org
No need to guess--you're correct. There are only two forces on the box parallel to the incline: the component of gravity and the kinetic friction.
 
Doc Al said:
No need to guess--you're correct. There are only two forces on the box parallel to the incline: the component of gravity and the kinetic friction.

Yeah, I just realized now how easy this question is. Thanks for confirming.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Block on top of an inclined plane, with a rough surface, that moves with constant acceleration
Replies
41
Views
3K
Physics — Net work on a box being pulled…
Replies
6
Views
2K
Static equilibrium | Uniform sphere on incline | Determining friction
Replies
43
Views
2K
Mass slipping on a moving inclined plane
Replies
5
Views
1K
Friction direction change in a inclined circular bend (car on a road)
Replies
11
Views
998
3D Statics problem: Box on an inclined plane constrained by a rope
Replies
19
Views
2K
Determining the angle while dealing with friction on an inclined plane
Replies
8
Views
3K
Box and a Spring on on an inclined plane
Replies
11
Views
3K
Inclined Plane Forces - with a twist
Replies
2
Views
1K
Rolling without slipping down an inclined plane
Replies
18
Views
5K

Hot Threads

Recent Insights

Back
Top