Finding the Norton Equivalent Circuit in a Short Circuited Circuit

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To find the Norton Equivalent Circuit in a short-circuited circuit, identify that the 2-ohm and 4-ohm resistors, along with the 33 A current source, are short-circuited, resulting in zero potential difference between points a and b. The short circuit affects the entire network, meaning the voltage across the 9-ohm resistor must be analyzed under these conditions. Nodal analysis can be applied to determine the short circuit current, which is essential for calculating the Norton equivalent. The method involves finding the open circuit voltage and dividing it by the short circuit current. Understanding these relationships is crucial for accurate circuit analysis.
chessmath
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Hi
Can you please tell me how to find the Norton Equivalent or I should say the short circuit current in the attachment diagram?

Norton resistance using two different methods but now question asks me to find resistance by dividing voltage of open circuit which I figure it out over current of short circuit.

What I know is 2 ohm resistor is going to be short circuited but I do not what I should do next, how to write nodal analysis for that?
can I say the 4 ohm and current source also are going to be short circuited or not?
Thanks.
 

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chessmath said:
Hi
Can you please tell me how to find the Norton Equivalent or I should say the short circuit current in the attachment diagram?

Norton resistance using two different methods but now question asks me to find resistance by dividing voltage of open circuit which I figure it out over current of short circuit.

What I know is 2 ohm resistor is going to be short circuited but I do not what I should do next, how to write nodal analysis for that?
can I say the 4 ohm and current source also are going to be short circuited or not?
Thanks.

There is a short circuit across both the 2 ohm and 4 ohm resistors and the 33 A current source as they all are connected to a and b. That means zero potential difference between a and b. What is the potential difference across the 9 ohm resistor then?

ehild
 

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