Finding the ODE that describes this circuit + find its transfer function

AI Thread Summary
The discussion focuses on deriving the second-order ordinary differential equation (ODE) for a circuit using Kirchhoff's Current Law (KCL) and finding its transfer function. The original poster struggles to express the node voltage at point A and has encountered issues with the polarity of the current equation for i1. Suggestions include using Laplace transforms for all components and summing currents at dependent nodes to simplify the process. Clarification on the relationship between node voltages and the application of Kirchhoff's Voltage Law is also sought. The conversation emphasizes the importance of correctly identifying voltage relationships to facilitate the derivation of the ODE and transfer function.
rugerts
Messages
153
Reaction score
11
Homework Statement
Find ODE that describes circuit in terms of capacitor voltage + find its transfer function (Vc/Vs)
Relevant Equations
Ohm's Law; Kirchhoff's Current Law and Voltage Law; Voltage across inductor; Current through
capacitor
IMG-1989.JPG
IMG-1990.JPG

As you can see, I've tried using KCL at node A to find the 2nd order ODE that describes this circuit in terms of the capacitor voltage. The problem I run into, however, is that I can't find anything to put the node voltage at A in terms of. I've tried (not shown here) doing mesh current as well, but ran into similar problems. Can anyone point me in the right direction? I'm certain that after this I'll be able to find the transfer function by applying a Laplace transform since the initial conditions are 0 to make things simple.
 
Physics news on Phys.org
rude man said:
2nd eq. for i1 is wrong (polarity).
Then substitute until you have VC = VC(VS).
Does this reconcile the issue that I can't find an expression for Va? Also, could you expand on why i1 would be wrong in terms of polarity?
 
rugerts said:
Does this reconcile the issue that I can't find an expression for Va?
Probably not.
Also, could you expand on why i1 would be wrong in terms of polarity?
If current flows from A to B then A is higher in voltage than B.

The way I would approach this problem is:
assign Laplace transform to all components. So L becomes Z=sL and C becomes Z=1/sC.

Then sum currents to zero at every dependent node (in your case 2). Don't use currents explicitly. For example, (V1-V2)/Z1 = (V2-V3)/Z2 + (V2-V4)/Z3 that sort of thing. This gets you your transfer function V(C)/V(S) = F(s) immediately.

To get the ODE I would take V(C) = F(s)V(S), multiply both sides by s, then go back to the time domain by s → d/dt and ##s^2## → ##d^2/dt^2##.

Of course there are ways of staying in the time domain but I'm not sure how to best do that so others might help you there.
 
  • Like
Likes rugerts
rugerts said:
I've tried using KCL at node A to find the 2nd order ODE that describes this circuit in terms of the capacitor voltage.
You have written the equation for ##i_c##[/color], the current through the capacitor and through the inductor, so the next step is to say

$$v_A\ =\ v_c\ +\ L\cdot\dfrac{di_c}{dt}$$
 
NascentOxygen said:
You have written the equation for ##i_c##, the current through the capacitor and through the inductor, so the next step is to say

$$v_A\ =\ v_c\ +\ L\cdot\dfrac{di_c}{dt}$$
See, I thought this was the case but couldn't justify it properly to myself. By what physical law is this true might I ask? Is this a consequence of Kirchhoff's Voltage Law?
 
rugerts said:
By what physical law is this true might I ask? Is this a consequence of Kirchhoff's Voltage Law?
The instantaneous voltage across multiple elements = the sum of their individual instantaneous voltages
 
Back
Top