Finding the POSITION of the center of mass

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SUMMARY

The center of mass for a system of three spheres with masses m, 3m, and 2m is calculated using the formulas for the first and zeroth moments of mass. The x-coordinate of the center of mass is determined to be (4/3)L, while the y-coordinate is correctly identified as 1.5L, which is halfway between 0L and 3L. The confusion arose from misinterpretation of the y-coordinate calculation, where the total moment was mistakenly calculated as 9mL instead of recognizing the correct midpoint. Clear understanding of the terminology and application of the formulas is essential for accurate computation.

PREREQUISITES
  • Understanding of center of mass concepts in physics
  • Familiarity with two-dimensional coordinate systems
  • Knowledge of mass distribution and its effect on center of mass
  • Proficiency in applying the first and zeroth moments of mass equations
NEXT STEPS
  • Study the derivation and application of the center of mass formulas in two dimensions
  • Learn about mass distribution and its implications in physics problems
  • Practice solving center of mass problems with varying mass distributions
  • Review video tutorials on calculating center of mass for complex systems
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to center of mass calculations.

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Homework Statement


Three spheres are placed around a coordinate grid: one of mass m at the bottom-left, one of mass 3m a distance of 3L above the first, and one of mass 2m a distance of 4L to the right of the first.
4 points between these three spheres are labeled: A near (1.3L, 1.5L), B near (2L, 1.3L), C near (1.1L, 0.7L), and D near (0.4L, L).
At which point would the center of mass be located?
Here is a video explanation of the solution, but I am totally confused on how this was calculated.



Homework Equations


The relevant equations that were derived in a prior video to this example were x (center of mass) = mass(i)*x-position(i) / m(i) , and this was rewritten as First Moment of the mass in x direction, or FM(x) = Σ m(sub i) * x(sub i) all over the Zeroth Moment of Mass in x direction, Σ m(sub i)

So this total formula was written as r (center of mass) = FM (r) / M

The Attempt at a Solution



I attempted the solution by looking at the other relevant equations, and must be confusing myself terribly. I know that this example is a two-dimensional system. So when I tried to apply the total r(center of mass) formula in the y-direction, what I'm doing is takign the mass of the three spheres and their relevant position in the y-direction and multiplying them together. Then adding their totals and dividing by the total mass of the system M.
......
In the x-direction, following the explanation given, I understood it as it was:

FM(x) = m(0) + 3m(0) + 2m(4L) = 8mL
And M = 6m

So if I divide 8mL by 6m, then that's (4/3)L in the x-direction.
......
I then attempted to do the same thing in the y-direction.

So FM(y) = m(0) + 2m(0) + 3m(3L) = 9mL
And M = 6m

So if I divide 9mL by 6m, I get (3/2)L as the position of the center of mass in the y-direction. However, the correct answer is saying it should be (1/2)L in the y-direction. How is this? What am I doing incorrectly with this formula?

I appreciate any help with this.
 
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You have the right answer, where did you see that L/2 in the y direction is the right answer? It isn’t even a choice! He said halfway between 0 and 3L. He probably could have been a bit more clear in his explanation , though.
 
omg... I feel so dumb sometimes.

The (halfway) I see now meant HALFWAY BETWEEN 0L and 3L in the y-direction which is 1.5L. Which I now see is equivalent to 9mL /6m.

The wording of these things always gets me confused. Thanks for helping to clear this up for me.
 

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