Finding the Value of sin(arctan(3)): Inverse Trig Functions Homework

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Homework Statement



Determine sin(arctan(3))

The Attempt at a Solution



I do not know how to start this. No special triangles : (.
 
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You try putting A=tan-1(3)

in which you would need to determine sinA.
 
rock.freak667 said:
You try putting A=tan-1(3)

in which you would need to determine sinA.

ahhh so could I write sinA = \theta?
 
Well I was thinking more along the lines of if A=arctan(3), then you can get tanA

and your problem was to find sin(arctan(3)) which becomes sin(A), which you can find by drawing suitable right angled triangles.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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