Finding the values of resistors

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To find the values of resistors using the voltage divider and Kirchhoff's Voltage Law (KVL), the resistors must be in series. The equivalent resistance (Req) is expressed as Req = (40*R2)/(40+R2), but R2 remains unknown initially. By applying KVL, the voltage across Req is determined to be 16V. Using the voltage divider equation, the relationship between the voltages and resistances leads to the calculation of R2 as 10 Ohms. The problem emphasizes the importance of combining KVL and Ohm's Law to solve for unknown resistor values effectively.
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Homework Statement


In the problem i have to find the values of resistors using voltage divider, and use KVL to determine the currents.


Homework Equations



Vi= [Ri / (R1+R2+...+Rn)] * Vs

1/Rtotal = 1/R1 + 1/R2 + ... + 1/Rn

Ʃrise + Ʃdrop = 0

The Attempt at a Solution



In order for us to use voltage divider the resistors must be in series.

Req = (40*R2)/(40+R2), but we still don't know the resistance of R2.

However, later I tried to use the KVL equation to find the voltage for Req.

-24+8+Veq = 0 → Veq = 16 V

Then I used the voltage divider equation:

Veq = [Req / (R1 + Req) ]* Vs // but again we have two unknowns here again

And that's the point where I stuck, I know this problem is trivial but my brain cannot come up with anything else to solve this.
 

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Using KVL, we know that Veq=24V-8V=16V. Using Ohm's Law, we can easily get R2=16V/1.6A=10 Ohms. The rest is obvious! :)
 
Thank you very much :D
 
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