Finding Velocity of a Dropped Shellfish

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To find the total velocity of the shellfish when it hits the ground, both vertical and horizontal components must be considered. The vertical velocity at impact, calculated using the equation vf² = vi² + 2ah, is approximately 24.3 m/s. The horizontal velocity remains constant at 15 m/s. The total velocity is then determined by combining these two components using the Pythagorean theorem, resulting in a final speed of 28.5 m/s. Neglecting air resistance simplifies the calculations, allowing for a straightforward application of physics principles.
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Homework Statement


5. A sea hawk flying horizontally at a speed of 15 m/s drops a shellfish from a height of 30 m. At what speed does the shellfish hit the ground? Neglect air resistance (drag).



Homework Equations



vf2 = vi2 + 2ah

The Attempt at a Solution



I got 24.3 which was one of the answers and when i emailed the professor he said that that was the vertical velocity and I need to look for total velocity...well the answer is 28.5 m/s and I don't understand how that was arrived.
 
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You could use conservation of energy here I believe.


Also, the horizontal velocity would be the same throughout.
 

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