First Order RL Circuit: Finding a Current I2(0-)

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Discussion Overview

The discussion revolves around the analysis of a first-order RL circuit, specifically focusing on finding the initial current i2(0-) just before a switch opens. Participants explore different methods of analysis, including mesh analysis and node voltage equations, while addressing discrepancies in calculated values.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant reports using mesh analysis and obtaining a value of -2 mA for i2(0-), while the textbook states it should be 15 mA, expressing confusion over the discrepancy.
  • Another participant suggests a method involving shorting the inductor to find the voltage at the central node and then applying Ohm's law to determine the initial currents i1 and i2.
  • A later reply provides a node voltage equation and calculates v=30 V, leading to a derived current i2(0-) of -1.5 mA, questioning why this method yields correct results while mesh analysis does not.
  • One participant raises a potential issue with the direction of i2 in the diagram, suggesting it may have been reversed, which could explain the confusion in the calculations.

Areas of Agreement / Disagreement

Participants express differing views on the effectiveness of mesh analysis versus node voltage methods, with no consensus on the correct approach or resolution of the discrepancies in calculated values.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the analysis, particularly concerning the direction of currents and the application of different circuit analysis methods.

johnsmith7565
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Homework Statement
The switch in the circuit in Fig. P7.1 has been closed for a long time before opening at t=0.

a. Finding i1(0-) and i2(0-). I am stuck on this.
Relevant Equations
Mesh equations

V1r1 + V2r2 + ... + VnRn = 0
IMG-3091.jpg
IMG-3092.jpg


I shorted the inductor and performed mesh analysis. The solutions to the linear system were done using a calculator. The book says that the value for i2(0-) should be 15 mA but I'm getting -2mA. What am I doing wrong? I'm completely confused. Maybe mesh isn't the most efficient way to find I2 but it should work, right?
 
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Currents are flowing at t=0, before switch is opened.
Short inductor, to find the voltage on the central node ?
Remove the short from the inductor after DC solution.
Then Ohms law to find initial currents i1 and i2 ?
What is inductor current ?
Switch opens, but current through inductor continues.
What are the currents i1 and i2 now ?
 
Baluncore said:
Currents are flowing at t=0, before switch is opened.
Short inductor, to find the voltage on the central node ?
Remove the short from the inductor after DC solution.
Then Ohms law to find initial currents i1 and i2 ?
What is inductor current ?
Switch opens, but current through inductor continues.
What are the currents i1 and i2 now ?

I’m going to do the first part of your question first.

Here is the node voltage equation:

(v-40)/500 + v/2000 + v/6000 = 0

Using a calculator I get v=30 V.

By ohms law: i2(0-) = -30/2000 = -0.0015 A. That’s right.
I1(0-) = 30/6000 = 0.005 A which is right. Why do I get the correct answers using the node voltage method but not by using the mesh method? That’s what confuses me.
 
I think you may have reversed the direction of i2 on the diagram.
Maybe you have as much trouble reading your writing as I do.
 

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