Fluid mechanics-Total energy line of static system

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SUMMARY

The discussion centers on the total energy line in a static fluid system involving two reservoirs connected by pipes, with one reservoir at a higher elevation than the other. The participants conclude that, since the flow velocity is zero, the total energy line will be a straight horizontal line starting from the water level of the higher reservoir and remaining parallel to the ground, despite the elevation difference. The Bernoulli equation is referenced, emphasizing that pressure does not affect the total energy line in a static condition.

PREREQUISITES
  • Understanding of Bernoulli's equation
  • Knowledge of fluid statics
  • Familiarity with concepts of potential energy in fluid systems
  • Basic principles of hydrostatics
NEXT STEPS
  • Study the implications of Bernoulli's equation in static fluid scenarios
  • Explore hydrostatic pressure calculations in varying elevations
  • Investigate the effects of pressure on fluid dynamics in non-static systems
  • Learn about energy conservation principles in fluid mechanics
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Students and professionals in fluid mechanics, civil engineers designing water distribution systems, and anyone interested in understanding the behavior of static fluids in reservoirs.

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I have two reservoirs, connected by two pipes. The first reservoir is higher in elevation than the second. If the system is full of static water, what would the total energy line look like?

Since the velocity of the flow through the system is 0, would the total energy line just be a straight line emerging from the water level of the higher reservoir and continuing parallel to the ground?
Or would it slant down due to the difference in elevation, following the slanting of the pipes? How would it end at the lower reservoir?

Thank you
 
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You must show some work answering your own questions. PF is not a HW oracle.
 
I'm sorry, I was trying to explain the extent of my reasoning in the second paragraph.
I will add more.

This is the Bernoulli equation:

z + (u^2/2g) + (P/pg) = Constant.
The velocity (u) being 0 simply follows on from my attempt at answering my own question.

Would the pressure have any effect?
 

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