Fluids rate of flow homework help

AI Thread Summary
The discussion revolves around calculating the cross-sectional areas and flow rates of two cylindrical pipes carrying an ideal fluid. The participants clarify that the cross-sectional area can be calculated using the formula A = πR², leading to areas of 4 cm² for Pipe A and 16 cm² for Pipe B. They also explore the relationship between flow rate and velocity, confirming that flow rate equals velocity multiplied by cross-sectional area. A participant calculates the flow rate for Pipe B as 0.20096 l/s and seeks advice on significant figures, concluding that the answer should be expressed with one significant figure as 0.2 l/s. The conversation emphasizes the importance of understanding the formulas and units involved in fluid flow calculations.
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Homework Statement



Two cylindrical pipes both carry an ideal fluid (zero viscosity) in laminar flow. Pipe A has radius Ra = 2 and flow velocity Va = 8cm/s. Pipe B has radius Rb = 4cm and flow velocity Vb = 4cm/s.

A) Calculate the cross section of pipe A and pipe B.
B) Calculate the rate of flow in liters/second (1l = 1000cm cubic)

Homework Equations



maybe v1a1 = v2a2 ?

The Attempt at a Solution



v1a1 = v2a2
= (8cm/s)(2cm) = (4cm/s)(4cm) = 1 ?

It`s wrong.
 
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okay. Now tell me what is a1, a2?
 


domyy said:

Homework Equations



maybe v1a1 = v2a2 ?
Just what do a_1 and a_2 represent?

Also, are these pipes connected end to end, or are they in parallel?
 


you mean...
 
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What has pressure got to do with it?

Go back to your first equation: what is a_1? This is not a trick question.
 


I have to calculate cross section of pipe A and B.

My book says cross-sectional area is VA.

I am confused with these formulas because I have the following:

Flow rate = VA
Flow rate = V/T

So, flow rate = cross sectional area = VA?
 
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R = 2 = area 1 = 4
R = 4 = area 2 = 16
?
 
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I think I know it...
 
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would that be correct?
 
  • #10


I just need this to finish my homework.
 
  • #11


I think I know it:

I think I am supposed to use pi. So, could it be: 3.14 x 4^2 = 50.24 for cross section pipe B?
 
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  • #12


I know the answer! I got the answer! I got the answer! Just a question: how should I leave the flow rate considering the answer for B = 0.20096, should I say the answer is 0.20 or 0.200 l/s ?
 
  • #13


domyy said:
I have to calculate cross section of pipe A and B.

My book says cross-sectional area is VA.
Assuming V is volume and A is area, something is wrong, either the book or your reading of it. The units are odd, too: \mathrm{L}^5. If V and A mean something else, then I don't know.

I am confused with these formulas because I have the following:

Flow rate = VA
Flow rate = V/T
What is T?

So, flow rate = cross sectional area = VA?
Think units. What units must flow rate have?
 
  • #14


domyy said:
I know the answer! I got the answer! I got the answer! Just a question: how should I leave the flow rate considering the answer for B = 0.20096, should I say the answer is 0.20 or 0.200 l/s ?
Since the problem, as you gave it, uses only one significant figure, then your answer should have no more than one significant figure.
 
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