Flux Density

  • Thread starter Kev1n
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1. A loop of wire is placed between the poles of a magnet. The magnetic field can be assumed uniform between the poles. The formed by the loop within the field of the magnet is 20cm2.
(i). Determine the magnitude of the flux density required to induce a maximum voltage of 1V when the loop is rotated at 6000rpm




2. E = 2 B l r ω



3. E = 2 B l r ω
We know E= 1v, lr = half A and ω = 6000 x 2Pi / 60

Therefore B = 2 x 0.5 x A x ω / E

So B = 2 x 0.5 x 20 x (6000 x 2Pi/60) / 1 = 12566Wb
Anyone check please, thanks
 

Answers and Replies

  • #2
Spinnor
Gold Member
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1. A loop of wire is placed between the poles of a magnet. The magnetic field can be assumed uniform between the poles. The formed by the loop within the field of the magnet is 20cm2.
(i). Determine the magnitude of the flux density required to induce a maximum voltage of 1V when the loop is rotated at 6000rpm




2. E = 2 B l r ω



3. E = 2 B l r ω
We know E= 1v, lr = half A and ω = 6000 x 2Pi / 60

Therefore B = 2 x 0.5 x A x ω / E

So B = 2 x 0.5 x 20 x (6000 x 2Pi/60) / 1 = 12566Wb
Anyone check please, thanks

Magnetic flux Phi = integral (B dot dA)

Phi = B*A*sin(wt)

Induced voltage E = -N*dPhi/dt where N in the number of turns which is one in your case.
 

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