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Let F=(7z+8)i+2zj+(2z+7)k, and let the point P=(abc), where a, b and c are constants. In this problem we will calculate div F in two different ways, first by using the geometric definition and second by using partial derivatives.
(a) Consider a (three-dimensional) box with four of its corners at (abc), (a+wbc), (ab+wc) and (abc+w), where w is a constant edge length. Find the flux through the box.
Thus, we have
div F(xyz)=lim/(w->0) = (BLANK/BLANK) = 2
I solved the div F to be 2... don't know how to solve for flux or the lim.
the lim in the textbook is written as lim ϵ-> 0 (3/4piϵ**3) o∫∫[F.NdS]
thanks for the help!
(a) Consider a (three-dimensional) box with four of its corners at (abc), (a+wbc), (ab+wc) and (abc+w), where w is a constant edge length. Find the flux through the box.
Thus, we have
div F(xyz)=lim/(w->0) = (BLANK/BLANK) = 2
I solved the div F to be 2... don't know how to solve for flux or the lim.
the lim in the textbook is written as lim ϵ-> 0 (3/4piϵ**3) o∫∫[F.NdS]
thanks for the help!