# Flux through a loop of wire in a magnetic field.

## Homework Statement

A uniform 4.5 T magnetic field passes perpendicularly through the plane of a wire loop .10 m^2 in area. What flux passes through the loop?

## Homework Equations

Flux = (B)(A)[cos(theta)]

## The Attempt at a Solution

Ok, according to my understanding. The equation should be set up as such:

flux = (4.5)(.10)[Cos(90)]

The cosine of 90 degrees, obviously, is zero therefore there should be no flux through the wire loop, correct? The answer sheet to this review is saying that the answer to this problem is

(b) .45 Tm^2

This would be true if the equation was the "sine of theta" rather than the cosine of theta, right? Is my equation wrong or is the review sheet wrong?!

Thanks,

-Will

Astronuc
Staff Emeritus
The normal to the plane of the loop is parallel to the B-field.

With respect to area, the area vector is perpendicular (normal) to the area surface by convention.

The normal to the plane of the loop is parallel to the B-field.

With respect to area, the area vector is perpendicular (normal) to the area surface by convention.

And perpendicular = 90 degrees, so my equation should reduce to zero because the cosine of 90 degrees is zero?

Or am I missing the point of your post? lol

Oh i get it! Haha, duh.

The normal is perpendicular to the surface making the angle 0 degrees. Cosine of 0 is 1. Yeah, I'm running on very little sleep, lol.

thanks, Astronuc.