Flux through cylinder problem: Finding the lateral area using vector calculus

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Homework Statement



Hey guys.

I have this question:

http://img122.imageshack.us/img122/2936/84391716.jpg

I think that the flux through the top and bottom is zero and that because A does not have a component in the z axis direction.
So all that got left is the lateral area.
Well, I get 0 and I don't know why. I'm suppose to get 120, I obviously have a mistake and I don't know where.
Can I please have some help?

Thanks


Homework Equations





The Attempt at a Solution

 
Last edited by a moderator:
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The normal vector to your cylinder certainly isn't (1,0,0), is it?
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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