How Long Does It Take for a Flywheel to Stop?

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A flywheel slows from an angular speed of 1.5 rad/s to a stop while completing 40 revolutions, which translates to an angular displacement of 80π radians. The discussion revolves around applying the correct rotational kinematic equations to find the time it takes to come to rest. Participants emphasize the importance of consistent units and the correct application of equations, such as Δθ = ω₀t + ½αt² and ω - ω₀ = αt. The conversation highlights confusion over the calculations and the need to eliminate variables for clarity. Ultimately, the contributors assist in clarifying the equations needed to solve the problem effectively.
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Homework Statement


A flywheel turns through 40 rev as it slows from an angular speed of 1.5 rad/s to a stop.Assuming a constant acceleration,find the tme for it to come to rest.

Homework Equations


##w-w_0=∝t##

The Attempt at a Solution


In Δt secon the change in w will be 1.5 and this time it will rotate 40 times..I tried every equaiton like
0-1.5=∝t
or
40=1.5t-1/2∝t^2
but I couldn't found
 
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Arman777 said:
40=1.5t-1/2∝t^2
but I couldn't found
There is another equation that you should know that involves initial and final velocities, acceleration and angle of rotation.
Also, you are mixing units here: revolutions and radians.
 
Check the units of your last equation (I wonder: why couldn't you solve it ? - or did it just give the wrong answer ?)
 
BvU said:
Check the units of your last equation (I wonder: why couldn't you solve it ? - or did it just give the wrong answer ?)

I am really bad at this whole rotation-torque subject.I ll look again..I know my equation is wrong...
 
What is the turning angle when the flywheel rotates 40 times?
Also check the signs.
 
ehild said:
What is the turning angle when the flywheel rotates 40 times?

turning angle ?
 
Arman777 said:
turning angle ?
Or angle of rotation. What is the angle the wheel rotates during one revolution?
 
ehild said:
Or angle of rotation. What is the angle the wheel rotates during one revolution?

2π ?
 
Are we turning 40 rev to 80π rad ??
 
  • #10
Arman777 said:
2π ?
yes. And during 40 revolutions?
 
  • #11
ehild said:
yes. And during 40 revolutions?

I posted 80π ?
 
  • #12
Arman777 said:
I posted 80π ?
Yes. So what are the equations for the change of angular velocity and angular rotation angle in time Δt?
 
  • #13
##w-w_0=∝t##and
##Δθ=wt ##

or ##Δθ=wt-\frac 1 2∝t^2##
 
  • #14
Arman777 said:
##w-w_0=∝t##and
##Δθ=wt ##

or ##Δθ=wt-\frac 1 2∝t^2##
Δθ=wt is only valid for constant angular velocity.
##Δθ=w_0t+\frac {1 }{2}\alpha t^2## that is valid with positive sign.
Eliminate alpha.
 
Last edited:
  • #15
I guess I have to study this more to understand the basics.I ll open another thread
 
  • #17
Δw=-1.5 and Δθ is 80 so

Δw=-1.5=∝t and

80=1.5t-1/21.5t

Is this true ?
 
  • #18
The rotational equations pretty much follow directly from the linear equations. So if you can remember the linear equations, the rotational should be easy.
v = vo + at → ω = ωo + αt
v2 = vo2 + 2ax → ω2 = ωo2 + 2αθ
x = vot + at2/2 → θ = ωot + αt2/2
F = ma → Γ = Iα
ρ = mv → L = Iω
Ek = mv2/2 → Ek = Iω2/2

Arman777 said:
80=1.5t-1/21.5t

Is this true ?
I think so, except it should be 80π instead of 80.
 
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  • #19
Ok,I found...Thanks all of you...Just couldn't see that
 
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