What Determines the Tension in the String Connecting Two Blocks?

[MFlood7356]

1. In Fig. 6-50, block 1 of mass 4.0 kg and block 2 of mass 6.6 kg are connected by a string of negligible mass and are initially held in place. Block 2 is on a frictionless surface tilted at θ = 38o. The coefficient of kinetic friction between block 1 and the horizontal surface is 0.18. The pulley has negligible mass and friction. Once they are released, the blocks move. What then is the tension in the string?

2. Block 1 force diagram:
Fnet = m1a
T - friction = m1a
T - (Uk*m1*g) = m1a
[T - Uk*m1*g] / m1 = a

Fnet = m2a
T - mgsinθ = m2a
{T - mgsinθ} / m2 = a

3. I then set the equations equal to each other to get [T - Uk*m1*g] / m1 = {T - mgsinθ} / m2 I went through and plugged the variables in and solved for T and I got 43N but I guess it's wrong. Can someone please help?

 

[AvroArrow]

Thank you!The tension in the string is 43 N. The equation you set up to solve for T is correct. You have solved it correctly.