Force Calculation in High Jump Takeoff

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SUMMARY

The discussion centers on the force calculation during a high jump takeoff, specifically addressing the forces exerted by a high jumper weighing 800N. The jumper exerts a force of 3 kN against the ground. According to Newton's Third Law, the ground exerts an equal and opposite force of 3 kN back on the jumper. The initial calculation attempted to derive acceleration using the formula a = f/m, but the correct interpretation relies on understanding the action-reaction principle.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Basic knowledge of force and weight conversion (N to kN)
  • Familiarity with the equation f = m x a
  • Concept of action-reaction pairs in physics
NEXT STEPS
  • Study Newton's Third Law of Motion in detail
  • Explore force and acceleration calculations in physics
  • Learn about the biomechanics of high jump techniques
  • Investigate the relationship between force exerted and ground reaction forces
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Physics students, sports scientists, coaches, and anyone interested in the mechanics of athletic performance, particularly in high jump techniques.

pennywise1234
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Homework Statement


A high jumper with a body weight of 800N exerts a force of 3 kN against the ground during takeoff.
How much force is exerted by the ground on the high jumper?

Homework Equations


f=m x a
a=f/m

The Attempt at a Solution


I converted 800n into KN giving me 0.8

I then divided a=3kn/0.8kn

is this right?

if not, how do i fix the issue
 
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Hint: It's a trick question! (Consider Newton's 3rd law.)
 
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so 3kn, because every action has equal and opposite reaction. thank you
 

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