How Much Force Did the Pitcher Exert on the Fastest Baseball Pitch?

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The fastest baseball pitch recorded was at 46 m/s, with the ball's mass being 145 g and the force exerted by the pitcher assumed to be horizontal and constant over a distance of 1.0 m. To calculate the force, the relationship between acceleration, initial velocity, final velocity, and distance must be utilized, as only velocity and mass are initially provided. The formula f=ma requires acceleration, which can be derived from the known variables. After some guidance, the solution was found by referencing the appropriate formula in the textbook. Understanding these principles is crucial for calculating the force exerted during the pitch.
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Homework Statement


The fastest pitched baseball was clocked at 46 m/s. If the pitcher exerted his force (assumed to be horizontal and constant) over a distance of 1.0 m, and a baseball has a mass of 145 g.
What force did the pitcher exert on the ball during this record-setting pitch?

Homework Equations


f=ma


The Attempt at a Solution


I know that Newtons are (kg*m)/sec^2, but I only have a velocity, not an acceleration, so I can't figure out the right force.
 
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kaiazad said:

Homework Statement


The fastest pitched baseball was clocked at 46 m/s. If the pitcher exerted his force (assumed to be horizontal and constant) over a distance of 1.0 m, and a baseball has a mass of 145 g.
What force did the pitcher exert on the ball during this record-setting pitch?

Homework Equations


f=ma

The Attempt at a Solution


I know that Newtons are (kg*m)/sec^2, but I only have a velocity, not an acceleration, so I can't figure out the right force.

Not to give away the answer: There is a formula that relates acceleration, initial velocity, final velocity, and distance traveled. Since you know three of the four items, with it you can find the acceleration, and hence the force.

Go find it in your textbook.
 
Figured it out! thanks!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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