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bobsmith76
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Homework Statement
A proton is projected into a magnetic field of 0.5 T directed into the page. If the proton is traveling at 3.4 × 10^5 m/s in a direction [up 28 ̊ right], what is the magnitude and direc- tion of the magnetic force on the proton?
Homework Equations
F = vBq(sin θ)
The Attempt at a Solution
(3.4 * 10^5)*(.5)(1.6*10^-19)(sin 28) = 1.27 * 10^-14
The book says the answer is 2.7 * 10^13
Maybe the charge for the proton is wrong.