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Force of an alpha particle

  1. Jan 16, 2012 #1
    1. The problem statement, all variables and given/known data

    A proton is projected into a magnetic field of 0.5 T directed into the page. If the proton is travelling at 3.4 × 10^5 m/s in a direction [up 28 ̊ right], what is the magnitude and direc- tion of the magnetic force on the proton?


    2. Relevant equations

    F = vBq(sin θ)


    3. The attempt at a solution

    (3.4 * 10^5)*(.5)(1.6*10^-19)(sin 28) = 1.27 * 10^-14

    The book says the answer is 2.7 * 10^13

    Maybe the charge for the proton is wrong.
     
  2. jcsd
  3. Jan 16, 2012 #2
    I am assuming that the magnetic field is perpendicular into the page.
    The direction of travel of the proton is not so clear.
     
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