Force of wheel Perependicular to road over speed hump

AI Thread Summary
The discussion focuses on calculating the upward force exerted by a car's wheel as it passes over a speed hump. The normal reaction force (Nr) is initially equal to the downward force of the car (Mg), but it increases as the wheel encounters the hump, resulting in an additional upward force (Ma). The participants explore how the speed of the car, specifically at 20 meters per second, affects this upward force. They note that if the road is straight, the vertical acceleration is zero, making the normal force equal to the weight of the car. However, if the road is curved, the normal force would need to account for vertical acceleration, complicating the calculation.
cjh1990
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Im curently trying to work out the upwards force of the wheel of a car as it passes over a hump in the road. I have drawn a very simple diagram to illustrate this. If anyone could help me calculate this force that would be most helpful.

I understand as the wheel is traveling along the road its normal reaction force (Nr) upwards is equal to that of the downwards force of the car (Mg) however when the wheel travels over the speed hump the normal reaction force increase as it is gains a greater upwards force (Ma).

if the car was traveling over the speed hump at 20 meteres per second what would be the upwards force of the wheel Ma ?








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hi cjh1990! :smile:

if the road is straight, then the vertical acceleration = 0, so normal force = weight

if the road is curved, then the vertical acceleration = … ?, so normal force = weight ± … ? :wink:
 

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