Force on one mass from another mass

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To determine the force acting on a 30kg cart from a 50kg cart when a 120N force is applied, the acceleration of the system must first be calculated. The total mass of the two carts in contact is considered, leading to an acceleration of 1.5 m/s². Once the acceleration is known, the force exerted by the 50kg cart on the 30kg cart can be calculated by multiplying the acceleration by the mass of the 30kg cart. Participants in the discussion emphasize the importance of analyzing the forces acting on each cart to arrive at the correct solution. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


Determine the force acting on a 30kg cart by a 50kg cart if the 30kg cart is pushed into the 50kg cart with a force of 120N.
m1=30kg
m2=50kg
Fa=120N

Homework Equations


FNET=ma
FNET=sigmaF

The Attempt at a Solution


Im really confused on where to start here. I was thinking of finding acceleration then substituting in for an FNET equation to find F of 2on1. Any tips on where to start would be helpful thanks.
 
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Drake M said:

Homework Statement


Determine the force acting on a 30kg cart by a 50kg cart if the 30kg cart is pushed into the 50kg cart with a force of 120N.
m1=30kg
m2=50kg
Fa=120N

Homework Equations


FNET=ma
FNET=sigmaF

The Attempt at a Solution


Im really confused on where to start here. I was thinking of finding acceleration then substituting in for an FNET equation to find F of 2on1. Any tips on where to start would be helpful thanks.
Is this the exact question, or have you paraphrased it?
I'm guessing we are to take the carts as initially in contact already, we are to ignore friction, and the 120N is a force applied to the 50kg cart.
If so, yes, consider acceleration. What will the acceleration be?
 
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Yes i have paraphrased it because it was c) of a question. To find acceleration would I combine the masses of the carts since theyre in contact? If I did then it would be
FNET=sigmaF
FNET=120N
FNET=ma
a=m/FNET
=80kg/120
.666m/s/s.
 
Drake M said:
FNET=ma
a=m/FNET
Try that again.
 
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Whoops...a would equal 1.5m/s/s.
So now that I have acceleration. would I just multiply it by the mass of the 50kg cart?
 
Drake M said:
Whoops...a would equal 1.5m/s/s.
So now that I have acceleration. would I just multiply it by the mass of the 50kg cart?
Maybe, but instead of just asking me, how about you try your own analysis? Pick one of the two carts and consider all the forces acting on it.
 
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Yeah Ill try to look further into it
 
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