Force Problem with football punter

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A football punter accelerates a 0.50 kg football from rest to 10 m/s in 0.20 seconds, prompting a discussion on calculating the average force exerted. The relevant equation is F = ma, where acceleration (a) is derived from the change in velocity over time. The correct calculation involves determining acceleration as 50 m/s², leading to an average force of 25 N. The confusion arose from misapplying the formula and not accounting for the time interval correctly. Understanding the relationship between force, mass, and acceleration clarifies the solution to the problem.
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[SOLVED] Force Problem

Homework Statement



2. A football punter accelerates a football from rest to a speed of 10m/s during the time in which his toe is in contact with the ball (about 0.20sec). If the football has a mass of 0.50kg, what average force does the punter exert on the ball?


Homework Equations


so far i have this and can't seem to find the equation(s) but i got some and does not correspond with the correct answer.

a=10ms/^2
t=.20sec
m=.50kg
F= that's what we need for answer

so F=ma


The Attempt at a Solution


but i don't understand how we put our time in an equation to solve for Force, I know I am missing something but i don't know what. I have the answer, answer only which does not help at all :P. Thats to check whether we get the correct problem

F = ma
F = 10m/s (.50kg)
F = 5N (?) but answer that was given was 25 N

I want to know how to do it :P even thou teacher gives us answer for homework. Which is the most important thing
I'm stuck with this help

Thank you in advance
 
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F = 10m/s (.50kg) is velocity * mass or mv which is the final momentum.

F = dp/dt or m dv/dt so take mass * (change in v)/(change in time)

a = dv/dt
 
Astronuc said:
F = 10m/s (.50kg) is velocity * mass or mv which is the final momentum.

F = dp/dt or m dv/dt so take mass * (change in v)/(change in time)

a = dv/dt

so F=ma:

F= 10ms/(.50kg) = 5 m/s correct which equals Velocity(?)

so for F= dp/dt what is dp? change in P(?) / change in time so we get

F= 5ms/.20s = 25N

my question comes from F=dp/dt we use that equation to find out Force? Where can we say that F=dp/dt (as u used) comes from?

srry if i sound confusing
 
p = m v = momentum.

Now let's take the case for constant mass.

F = dp/dt = d (mv) /dt = m dv/dt = m a

Back the problem.

m = 0.5 kg, which is accelerated from rest (v=0) such that at the end of 0.2 s, the mass has a velocity 10 m/s. So the change in velocity (dv) = 10 m/s - 0 m/s, and the change it time (or time interval), dt = 0.2 s.

so F = ma = m dv/dt

m = 0.5 kg, dv = 10 m/s, and dt = 0.2 s
 
got it :p that helped out
 
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