What Is the Maximum Value of Static Friction Coefficient to Move a 10kg Object?

AI Thread Summary
To determine the maximum static friction coefficient (Ms) for moving a 10kg object, a force of 50N is required to start it from rest. The normal force (Fn) is calculated as the weight of the object, which is 98N (10kg multiplied by the acceleration due to gravity). The relationship between the frictional force (Ff), normal force, and static friction coefficient is given by the equation Ff = Fn * Ms. By substituting the known values into the equation, Ms is found to be approximately 0.5. This indicates that the maximum value of the static friction coefficient for the object is 0.5.
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Homework Statement


A force of 50N is required to start a 10kg object moving from rest. What is the maximum value that (Ms) could be?
A)5
b).05
c).5
d).1
Any help would be greatly appreciated thanks.


Homework Equations





The Attempt at a Solution

 
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You'll have to start us out here. What's the normal force and what does the normal force have to do with static friction?
 
Normal force is the force acting up on the object so the higher the normal force the less kinetic friction it takes to get the object moving. I can't find the normal force though.
 
Exactly backwards. Frictional force is related to normal force times the Ms. So larger normal force means more friction. I think you might need to look in a book. How is the normal force related to weight? How is weight related to mass?
 
I was trying to use this equation Ff=FnMs, but there are 2 unknowns so i can't solve for it
 
I think the answer would be .5
Ff=FnMs
50=98Ms
Ms=.5(rounded)
 
You've got it. Fn=mg by balancing the vertical forces.
 
Thank you
 

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