Calculating Forces on Boxcars in a Train: Newtons and Acceleration

  • Thread starter Thread starter waldvocm
  • Start date Start date
  • Tags Tags
    Forces
AI Thread Summary
The discussion revolves around calculating the forces acting on boxcars in a train system, focusing on a locomotive and two boxcars with different masses. The acceleration of the train is given as 0.578 m/s², leading to calculations of the forces between the boxcars and between the locomotive and the first boxcar. It is clarified that the forces between the boxcars differ due to their varying masses, with the correct force for the second boxcar being 9421.4 N. Additionally, the force exerted by the tracks on the locomotive is calculated to be 42140 N. The importance of labeling forces and applying Newton's laws accurately is emphasized for clarity in calculations.
waldvocm
Messages
76
Reaction score
0
A train consists of a 4300kg locomotive pulling two loaded boxcars. The first boxcar has a mass of 12,700kg and the second 16,300kg. Presume that the boxcar wheels roll without friction and ignore aerodynamics. The acceleration of the train is 0.578m/s^2
a)With what force, in Newtons, do the boxcars pull on each other?

I am confused here. Do they pull on each other with the same force? They can't since they don't weigh the same, correct?

0.578=T/12700 T=7340.6

0.578=T/16300 T=9421.4


b) With what force do the locomotive and first boxcar pull on each other?

I can use the same steps from a) for this one

c)With what force must the tracks push on the locomotive?

would the force be equal to the weight?
 
Physics news on Phys.org
waldvocm said:
Do they pull on each other with the same force? They can't since they don't weigh the same, correct?
What does Newton's 3rd law tell you?

0.578=T/12700 T=7340.6

0.578=T/16300 T=9421.4
Don't confuse the net force on a car with the force between the cars.

First things first. Draw diagrams of each car, showing the forces acting on it. Then apply Newton's laws as needed.
 
a) boxcars pull on each other
F=16300(0.578)=9421.4

b)The locomotive pull on the first boxcar
F=12700+16300(0.578)=16762

c)The tracks push on the locomotive
F=4300(9.80)=42140

Are these formulas correct?
 
waldvocm said:
a) boxcars pull on each other
F=16300(0.578)=9421.4

b)The locomotive pull on the first boxcar
F=12700+16300(0.578)=16762

c)The tracks push on the locomotive
F=4300(9.80)=42140

Are these formulas correct?
The first answer is correct, but the others are not. I suggest that you label the forces--for example, F1-2, FL-1, and Ft-L--then write force equations for each car.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

Similar threads

Back
Top