Formula of an inverse function

wertlewoo2
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Homework Statement


Find the formula of the inverse function of f(x)=300/(3+15e^.05x).


Homework Equations



f(x)=300/(3+15e^.05x)

The Attempt at a Solution



I'm definitely way off but I got .05y(5x)+ln100=lnx. What I did was multiple the denominator by the y(cross mltiplication) and then tried to factor out e.
 
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So you start with y = 300 / (3 + 15 e^(x/20)

and do the cross product trick to get y * (3 + 15e^(x/20)) = 300

and then to:

3 + 15e^(x/20) = 300 / y

Does this help?

You should now move terms and factors to the y side and you should then be able to isolate everything
so that you get x = ...
 
@Jedishrfu Thanks so much that was really helpful! Last question do you know how you could be able to take the ln of e to simplify the equation?
 
wertlewoo2 said:
@Jedishrfu Thanks so much that was really helpful! Last question do you know how you could be able to take the ln of e to simplify the equation?
I'm sure he does. The real question is do you know how? If you do, take a stab at it.

If you don't, review the properties of logarithms.
 
Mark44 said:
I'm sure he does. The real question is do you know how? If you do, take a stab at it.

If you don't, review the properties of logarithms.

:smile:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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