Fourier transform of complex exponential multiplied to unit step

AI Thread Summary
The discussion focuses on finding the Fourier transform of the function v(t) = exp(-i*wo*t)*u(t), where u(t) is the unit step function. The initial attempt at the solution involves integrating the product of v(t) and exp(-i*w*t) over the appropriate limits, leading to an expression that was deemed incorrect. A correction was suggested, emphasizing the need to consider the behavior of the exponential function during integration, particularly when ω = -ω0. The final correct form of the Fourier transform includes both a fractional term and a delta function, specifically 1/(i2π(f+f0)) + 1/2δ(f+f0).
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Homework Statement


find the Fourier transform of complex exponential multiplied to a unit step.
given: v(t)=exp(-i*wo*t)*u(t)

Homework Equations



∫(v(t)*exp(-i*w*t) dt) from -∞ to +∞


The Attempt at a Solution



∫([v(t)]*exp(-i*w*t) dt) from -∞ to +∞
=∫([exp(-i*wo*t)*u(t)]*exp(-i*w*t) dt) from -∞ to +∞
=∫([exp(-i*wo*t)]*exp(-i*w*t) dt) from 0 to +∞
=1/(w0+w)

is this correct? help :frown:
 
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No, this is not correct. Go back to your 2nd to last equation
V=\int^\infty_0{exp[-i(\omega+\omega_0)t]dt}
and think about what you are integrating over. The exponential oscillates wildly unless

\omega=-\omega_0

What does that tell you?
(For a further hint, look up delta functions in your textbook.)
 
i've seen this transform: v(t)*e^(j*(wo)*t)<--->V(f-fo)

and letting u(t)=v(t)

where u(t)<--->1/(2*pi*f) +δ(f)/2

so, exp(-i*wo*t)*u(t)=1/(2*pi*(f+fo)) +δ(f+fo)/2is this correct?
 
Almost! You are missing an i (or j):

\frac{1}{i2\pi (f+f_0)}+\frac{1}{2}\delta(f+f_0)
 
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