Free body diagram for mass on oscillating spring

AI Thread Summary
The discussion focuses on the free body diagram (FBD) for a mass on an oscillating spring at its midpoint. At this position, the spring force and weight force are equal, resulting in no net force acting on the mass. Consequently, the acceleration of the mass is zero, indicating that it is in equilibrium. The key point is that at the midpoint, the restoring force of the spring is balanced by the weight of the mass, leading to a simplified FBD that primarily includes the weight force. Overall, understanding the forces at this equilibrium position clarifies the dynamics of the oscillating system.
physics20
Messages
5
Reaction score
0

Homework Statement


What does the free body diagram look like for a mass on an oscillating spring, when the mass is at its midpoint.


Homework Equations


F=-kx


The Attempt at a Solution


I'm not sure how an oscillating spring FBD is different from one for a non-oscillating spring. I don't know what to include other than an upward directed spring force and a downward directed weight force.

Also, For a mass on spring with a mass m and spring constant k (if the mass was not oscillating the spring would be extended a length L), what is the directions and relative magnitudes of the accelerations at the bottom and at the midpoint?
 
Physics news on Phys.org


Welcome to PF!

Remember that the spring restoring force depends upon the displacement from the equilibrium position. So, if the mass is oscillating, the force will vary depending upon where in the oscillation the mass is. If it is at that midpoint, this IS the spring's equilibrium position. Hence, the displacement from the equilibrium position (x) equals 0. So...is there any spring restoring force acting at that position?
 


No there isn't. So does that mean that the free body diagram at the midpoint would only have the downward force of the weight of the mass?

And would that also mean that the acceleration of the mass when it is at the midpoint is 0 (because acceleration is also dependent on the displacement)?
 


Hmmm...well if it's a vertical system, then I guess the definition of "equilibrium position" changes. The midpoint of the oscillation will be the point at which all the forces are balanced (and hence the acceleration is indeed zero). This point will occur not when the spring is completely unextended or uncompressed, but rather when the spring is extended just enough that the restoring force balances the weight. So I was not quite correct above.
 


Ok that makes sense, except I'm still confused about what forces to include on the free body diagram for the mass when its at the midpoint. Is it just the weight force, or is there a spring force that I also have to account for?
 


physics20 said:
Ok that makes sense, except I'm still confused about what forces to include on the free body diagram for the mass when its at the midpoint. Is it just the weight force, or is there a spring force that I also have to account for?

I answered this question in my previous post. At the midpoint, the system is in equilibrium, meaning that all forces are balanced. I said that.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top