Free fall of straight wire in a homogeneous magnetic field

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SUMMARY

A straight horizontal wire falling freely in a homogeneous horizontal magnetic field generates an electromotive force (EMF) due to its motion. The equations discussed include E = Blv = Blgt for instantaneous EMF and E = ΔΦ/Δt = BΔA/Δt = 1/2Blgt for average EMF. The difference of 1/2 arises because the first equation calculates instantaneous velocity, while the second uses average velocity over time. Both equations are valid but apply to different contexts of motion.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Basic knowledge of kinematics, specifically free fall motion
  • Familiarity with the concept of electromagnetic force (EMF)
  • Ability to differentiate between instantaneous and average quantities in physics
NEXT STEPS
  • Study Faraday's Law of Electromagnetic Induction in detail
  • Explore kinematic equations for uniformly accelerated motion
  • Learn about the relationship between velocity and EMF in electromagnetic systems
  • Investigate the effects of varying magnetic fields on induced EMF
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Students studying physics, particularly those focusing on electromagnetism and kinematics, as well as educators looking for practical examples of electromagnetic induction concepts.

alkmini
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hello every body. I have a high school problem
a straight horizontal wire is falling freely in a homogeneous horizontal magnetic field, perpendicular to the wire and i want to find the inductive voltage.
I said E= Blv=Blgt
But I can also say E=ΔΦ/Δt=BΔΑ/Δt=Βl1/2gt [t][2]/Δt=1/2Blgt
why doew this difference of 1/2 arise?
 
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Hummm...

Your problem arises because of something like this:v = gt, but... v = 1/2gt too?

That's because on the first equation, you were finding INSTANTANEOUS velocity, so therefore INSTANTANEOUS EMF.
On the second equation, you somehow got average velocity... I'm still trying to figure it out.

A-ha! Okay, I think I got it figured out.
When you substituted 1/2gt for X, and divided by t to get 1/2gt, you actually found the average velocity, since it's NOT instantaneous velocity. The velocity constantly changes because the wire is accelerating.

Both of your equations are right, except the first one is instantaneous EMF after a certain T, and the second equation is average EMF with respect to T.
 
Last edited:
thanks a lot
 

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