Frequency of Pendulum on Moon: 1.18 Hz

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The discussion focuses on calculating the frequency and period of a pendulum on the Moon. The pendulum has a mass of 0.070 kg and an initial period of 0.704 seconds, leading to a frequency of 1.42 Hz. When attempting to find the period on the Moon, the user incorrectly calculated the length of the pendulum, initially arriving at 12.1 m instead of the correct 12.3 cm. The gravitational acceleration on the Moon is noted as 1.67 m/s², which affects the period calculation. The importance of correctly applying the gravitational value under the square-root sign in the formula is emphasized.
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A pendulum consists of a mass m = 0.070 kg hanging from a flexible string of length L. The string is very thin, very light, and doesn't stretch much. It makes small oscillations, with a period of 0.704 s. Find the oscillation frequency of the pendulum. Neglect any air resistance.
I got this part ok.. the answer was 1.42 Hz.
The next part says.. Find the period of the same pendulum on the moon's surface. The gravitational acceleration of the moon is 1.67 m/s^2.
I used the equation
T= 2\pi \sqrt L/g
.704 = 2\pi \sqrt L/9.8
Solving for L gave me 12.1 m
I then used this equation for the period on the moon
T= 2\pi \sqrt 12.1/1.67
T= 16.9 s, which wasn't right.
Can someone help? Thanks.
 
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The length is wrong.
I get about 12.3 cm

Remember, the g-value is under the square-root sign
 
Ok I got it.. thanks!
 

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