Frobenius Equation 1: Almost there

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Hi :smile: I think I am making some good progress on this one, but I am unsure of what the next step is? Can someone give a nudge in the right direction?

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Any thoughts on this one? It is the Frobenius case where the roots of the indicial equation differ by an integer. I have used the larger root to find y1(x) and now I am
seeking y2(x) = k*y1(x)*ln(x) + Σdnxn+s1 where s1 is the smaller root that I found. I have to find the dn's and I also have that 'k' to deal with.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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