Fundamental electrokinetics problem calculation using Ohm's Law

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The discussion revolves around calculating the voltage drop and terminal voltage in a circuit with a consumer resistance of 2 ohms, an internal resistance of 0.3 ohms, and a voltage supply of 130 V. Participants are attempting to apply Ohm's Law, specifically using the formula I=V/Rtotal, where Rtotal includes both the consumer and internal resistances. There is confusion regarding the role of connecting threads, which have a resistance of 0.15 ohms each, and how they factor into the overall calculations. Clarification is sought on how to determine the voltage drop across the internal resistance and the terminal voltage of the battery. The conversation emphasizes the need for a clear understanding of circuit components and their contributions to voltage and resistance.
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Homework Statement
Please help me to find the voltage drop of the wire, and the terminal voltage.
Relevant Equations
R=V/I (Ohm's law)
For a consumer with a resistance of 2 ohms, it has an internal resistance of 0.3 ohms and a voltage of 130 Vwe switch on the power source. The resistance of each connecting thread is 0.15 ohms. What is the voltage drop on the line and what is the terminal voltage?
 
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Please show your work and tell us where you're stuck.
 
I can find the current flow with the equation I=V/Rtotal,
where Rtotal=R1+R2 and R1=2 ohm
R2=0,3 ohm

but after this I do not know how to continue. Hence I thought to use the electrical resistence of the wire for solving the problem, but I can't figure out how to use it correctly.
I would appreciate some guidance.
 
annin said:
Homework Statement: Please help me to find the voltage drop of the wire, and the terminal voltage.
Relevant Equations: R=V/I (Ohm's law)

For a consumer with a resistance of 2 ohms, it has an internal resistance of 0.3 ohms and a voltage of 130 Vwe switch on the power source. The resistance of each connecting thread is 0.15 ohms. What is the voltage drop on the line and what is the terminal voltage?
annin said:
I can find the current flow with the equation I=V/Rtotal,
where Rtotal=R1+R2 and R1=2 ohm
R2=0,3 ohm

but after this I do not know how to continue. Hence I thought to use the electrical resistence of the wire for solving the problem, but I can't figure out how to use it correctly.
I would appreciate some guidance.
Is there a diagram that goes with this problem? I'm not understanding what is being asked. (Use the "Attach files" link below the Edit window to upload a diagram of the problem.)
 
annin said:
it has an internal resistance
"It" being a battery?
annin said:
I can find the current flow with the equation I=V/Rtotal,
where Rtotal=R1+R2 and R1=2 ohm
R2=0,3 ohm
What about these "connecting threads"? What are they and where are they in the circuit?
annin said:
What is the voltage drop on the line
What line? No line was mentioned before. Is it the "threads"?
annin said:
what is the terminal voltage?
Think of the battery with internal resistance as two parts, an ideal battery (no internal resistance) with a resistor in series. The voltage across the ideal battery is 130V. Given the current in the circuit, what is the voltage drop across the internal resistance?
 

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