Galvanic Cell Changes: Copper Deposition on X

AI Thread Summary
During electrolysis, 1.05 g of copper is deposited on electrode X, leading to a calculation of 0.01667 mol of Cu and 0.0333 mol of electrons transferred. This indicates that 3.60 g of silver is lost from electrode W, supporting option A as correct. However, there is confusion regarding the role of Z, which is mistakenly identified as a wire instead of a salt bridge. The discussion highlights the importance of understanding the flow of electrons and the roles of different components in a galvanic cell. Clarification on these points is needed to resolve the misunderstanding.
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Homework Statement


During electrolysis in the cell below, 1.05 g copper is deposited on electrode X. Which one of the following statements is correct?

(Relative atomic masses Cu = 63, Ag = 108).
Screen Shot 2016-07-01 at 3.36.05 PM.png

  1. A) The mass of silver electrode W decreases by 3.60 g.
  2. B) The mass of silver deposited on electrode Y during the electrolysis is 1.80 g.
  3. C) Z is a salt-bridge.
  4. D) The concentration of copper ions in solution decreases during the electrolysis.
  5. E) The flow of negative charge is from right to left in Z.

Homework Equations

The Attempt at a Solution



I chose A. Since 1.05g of Cu is deposited, there are 0.01667 mol of Cu deposited. This means there are 0.0333 mol of electrons transferred. Which means there are 0.0333 mol of Ag lost in the anode. This means the anode lost 3.60g of Ag. However, C also makes sense as Z is the salt bridge. Could someone tell me where I went wrong?
 
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Z is a wire.
 
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